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	<title>Comments on: The DynamicRSS PHP&#160;Class</title>
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		<title>By: Marv</title>
		<link>http://abeautifulsite.net/blog/2008/12/the-dynamicrss-php-class/#comment-773</link>
		<dc:creator>Marv</dc:creator>
		<pubDate>Fri, 19 Dec 2008 18:11:33 +0000</pubDate>
		<guid isPermaLink="false">http://abs.lavitech.com/2008/12/the-dynamicrss-php-class/#comment-773</guid>
		<description>In my situation, in garnering the category name in the original query meant doing a left join between two tables ... one table where the articles are ... and the other where the categories are (the names of the categories).  This initial query using the join is necessary to get the articles grouped in their respective categories.

After a little monkeying around, I made a separate mysql query for the category name directly from its own table and made a variable for it.  Passing that variable into the channel() worked perfectly.

Thank you for the heads up on that. :)</description>
		<content:encoded><![CDATA[<p>In my situation, in garnering the category name in the original query meant doing a left join between two tables &#8230; one table where the articles are &#8230; and the other where the categories are (the names of the categories).  This initial query using the join is necessary to get the articles grouped in their respective categories.</p>
<p>After a little monkeying around, I made a separate mysql query for the category name directly from its own table and made a variable for it.  Passing that variable into the channel() worked perfectly.</p>
<p>Thank you for the heads up on that. :)</p>
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		<title>By: Cory LaViska</title>
		<link>http://abeautifulsite.net/blog/2008/12/the-dynamicrss-php-class/#comment-772</link>
		<dc:creator>Cory LaViska</dc:creator>
		<pubDate>Fri, 19 Dec 2008 16:03:26 +0000</pubDate>
		<guid isPermaLink="false">http://abs.lavitech.com/2008/12/the-dynamicrss-php-class/#comment-772</guid>
		<description>@Marv: can you get the category name in a variable and pass it to the channel() method?</description>
		<content:encoded><![CDATA[<p>@Marv: can you get the category name in a variable and pass it to the channel() method?</p>
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		<title>By: Marv</title>
		<link>http://abeautifulsite.net/blog/2008/12/the-dynamicrss-php-class/#comment-771</link>
		<dc:creator>Marv</dc:creator>
		<pubDate>Fri, 19 Dec 2008 02:55:24 +0000</pubDate>
		<guid isPermaLink="false">http://abs.lavitech.com/2008/12/the-dynamicrss-php-class/#comment-771</guid>
		<description>I&#039;ve been searching a while for a good rss class script to modify one of my sites.  Our site has a series of articles in various categories and I&#039;ve been able to run the The DynamicRSS PHP Class so that I can obtain the latest RSS feeds for each category.  But I&#039;m scratching my head on one wee little obstacle.

My query that I use calls for the categoryname but I cannot figure out how to incorporate it into the channel array so that my different category feeds can have their appropriate category name within the channel title.</description>
		<content:encoded><![CDATA[<p>I&#8217;ve been searching a while for a good rss class script to modify one of my sites.  Our site has a series of articles in various categories and I&#8217;ve been able to run the The DynamicRSS PHP Class so that I can obtain the latest RSS feeds for each category.  But I&#8217;m scratching my head on one wee little obstacle.</p>
<p>My query that I use calls for the categoryname but I cannot figure out how to incorporate it into the channel array so that my different category feeds can have their appropriate category name within the channel title.</p>
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